186. C Program to Convert Numbers into Words Using Switch Case.
How does this program work?
- This Program is used to search a word from the given string.
Here is the code
#include <stdio.h>
#include <math.h>
int main()
{
int n, num = 0, digits;
// Input number
printf( "Enter any number to print in words: \n");
scanf("%d", &n);
// Find total digits in n
digits = (int) log10(n);
//Store reverse of n in num
while(n != 0)
{
num = (num * 10) + (n % 10);
n /= 10;
}
// Find total trailing zeros
digits = digits - ((int) log10(num));
//Extract last digit of number and print corresponding number in words till num becomes 0
while(num != 0)
{
switch(num % 10)
{
case 0:
printf("Zero ");
break;
case 1:
printf("One ");
break;
case 2:
printf("Two ");
break;
case 3:
printf("Three ");
break;
case 4:
printf("Four ");
break;
case 5:
printf("Five ");
break;
case 6:
printf("Six ");
break;
case 7:
printf("Seven ");
break;
case 8:
printf("Eight ");
break;
case 9:
printf("Nine ");
break;
}
num /= 10;
}
//Print all trailing zeros
while( digits)
{
printf("Zero ");
digits--;
}
return 0;
}
